Many functions build lists, as lists reside at the very heart of Lisp.
cons
is the fundamental list-building function; however, it is
interesting to note that list
is used more times in the source
code for Emacs than cons
.
This function is the most basic function for building new list structure. It creates a new cons cell, making object1 the CAR, and object2 the CDR. It then returns the new cons cell. The arguments object1 and object2 may be any Lisp objects, but most often object2 is a list.
(cons 1 '(2)) ⇒ (1 2)
(cons 1 '()) ⇒ (1)
(cons 1 2) ⇒ (1 . 2)
cons
is often used to add a single element to the front of a
list. This is called consing the element onto the list.
5
For example:
(setq list (cons newelt list))
Note that there is no conflict between the variable named list
used in this example and the function named list
described below;
any symbol can serve both purposes.
This function creates a list with objects as its elements. The
resulting list is always nil
-terminated. If no objects
are given, the empty list is returned.
(list 1 2 3 4 5) ⇒ (1 2 3 4 5)
(list 1 2 '(3 4 5) 'foo) ⇒ (1 2 (3 4 5) foo)
(list) ⇒ nil
This function creates a list of length elements, in which each
element is object. Compare make-list
with
make-string
(see Creating Strings).
(make-list 3 'pigs) ⇒ (pigs pigs pigs)
(make-list 0 'pigs) ⇒ nil
(setq l (make-list 3 '(a b))) ⇒ ((a b) (a b) (a b)) (eq (car l) (cadr l)) ⇒ t
This function returns a list containing all the elements of
sequences. The sequences may be lists, vectors,
bool-vectors, or strings, but the last one should usually be a list.
All arguments except the last one are copied, so none of the arguments
is altered. (See nconc
in Functions that Rearrange Lists, for a way to join
lists with no copying.)
More generally, the final argument to append
may be any Lisp
object. The final argument is not copied or converted; it becomes the
CDR of the last cons cell in the new list. If the final argument
is itself a list, then its elements become in effect elements of the
result list. If the final element is not a list, the result is a
dotted list since its final CDR is not nil
as required
in a proper list (see Lists and Cons Cells).
Here is an example of using append
:
(setq trees '(pine oak)) ⇒ (pine oak) (setq more-trees (append '(maple birch) trees)) ⇒ (maple birch pine oak)
trees ⇒ (pine oak) more-trees ⇒ (maple birch pine oak)
(eq trees (cdr (cdr more-trees))) ⇒ t
You can see how append
works by looking at a box diagram. The
variable trees
is set to the list (pine oak)
and then the
variable more-trees
is set to the list (maple birch pine
oak)
. However, the variable trees
continues to refer to the
original list:
more-trees trees | | | --- --- --- --- -> --- --- --- --- --> | | |--> | | |--> | | |--> | | |--> nil --- --- --- --- --- --- --- --- | | | | | | | | --> maple -->birch --> pine --> oak
An empty sequence contributes nothing to the value returned by
append
. As a consequence of this, a final nil
argument
forces a copy of the previous argument:
trees ⇒ (pine oak)
(setq wood (append trees nil)) ⇒ (pine oak)
wood ⇒ (pine oak)
(eq wood trees) ⇒ nil
This once was the usual way to copy a list, before the function
copy-sequence
was invented. See Sequences, Arrays, and Vectors.
Here we show the use of vectors and strings as arguments to append
:
(append [a b] "cd" nil) ⇒ (a b 99 100)
With the help of apply
(see Calling Functions), we can append
all the lists in a list of lists:
(apply 'append '((a b c) nil (x y z) nil)) ⇒ (a b c x y z)
If no sequences are given, nil
is returned:
(append) ⇒ nil
Here are some examples where the final argument is not a list:
(append '(x y) 'z) ⇒ (x y . z) (append '(x y) [z]) ⇒ (x y . [z])
The second example shows that when the final argument is a sequence but not a list, the sequence’s elements do not become elements of the resulting list. Instead, the sequence becomes the final CDR, like any other non-list final argument.
This function returns a copy of the tree tree. If tree is a cons cell, this makes a new cons cell with the same CAR and CDR, then recursively copies the CAR and CDR in the same way.
Normally, when tree is anything other than a cons cell,
copy-tree
simply returns tree. However, if vecp is
non-nil
, it copies vectors too (and operates recursively on
their elements).
This function returns a “flattened” copy of tree, that is,
a list containing all the non-nil
terminal nodes, or leaves, of
the tree of cons cells rooted at tree. Leaves in the returned
list are in the same order as in tree.
(flatten-tree '(1 (2 . 3) nil (4 5 (6)) 7)) ⇒(1 2 3 4 5 6 7)
This function returns object as a list. If object is already a list, the function returns it; otherwise, the function returns a one-element list containing object.
This is usually useful if you have a variable that may or may not be a list, and you can then say, for instance:
(dolist (elem (ensure-list foo)) (princ elem))
This function returns a list of numbers starting with from and
incrementing by separation, and ending at or just before
to. separation can be positive or negative and defaults
to 1. If to is nil
or numerically equal to from,
the value is the one-element list (from)
. If to is
less than from with a positive separation, or greater than
from with a negative separation, the value is nil
because those arguments specify an empty sequence.
If separation is 0 and to is neither nil
nor
numerically equal to from, number-sequence
signals an
error, since those arguments specify an infinite sequence.
All arguments are numbers.
Floating-point arguments can be tricky, because floating-point
arithmetic is inexact. For instance, depending on the machine, it may
quite well happen that (number-sequence 0.4 0.6 0.2)
returns
the one element list (0.4)
, whereas
(number-sequence 0.4 0.8 0.2)
returns a list with three
elements. The nth element of the list is computed by the exact
formula (+ from (* n separation))
. Thus, if
one wants to make sure that to is included in the list, one can
pass an expression of this exact type for to. Alternatively,
one can replace to with a slightly larger value (or a slightly
more negative value if separation is negative).
Some examples:
(number-sequence 4 9) ⇒ (4 5 6 7 8 9) (number-sequence 9 4 -1) ⇒ (9 8 7 6 5 4) (number-sequence 9 4 -2) ⇒ (9 7 5) (number-sequence 8) ⇒ (8) (number-sequence 8 5) ⇒ nil (number-sequence 5 8 -1) ⇒ nil (number-sequence 1.5 6 2) ⇒ (1.5 3.5 5.5)
There is no strictly equivalent way to add an element to
the end of a list. You can use (append listname (list
newelt))
, which creates a whole new list by copying listname
and adding newelt to its end. Or you can use (nconc
listname (list newelt))
, which modifies listname
by following all the CDRs and then replacing the terminating
nil
. Compare this to adding an element to the beginning of a
list with cons
, which neither copies nor modifies the list.