A car A travel with a velocity of 110 km/h, in some moment pass together a B car, that is in rest. 4 seconds after, the car B start with an acceleration of 2.6 m/s2 in chase to the car A. How seconds need to be 5 meters behind the car A?
Solution with FisicaLab
Erase the content of the chalkboard. And add one element Mobile in X, one element Mobile in X with constant velocity, one element Distance XY, and one element Stationary reference system. As show the image below:
The end time is an unknown data:
We assume that the car A is moving in the direction of the positive X axis. And that both cars start from the origin. The car A is the element Mobile in X with constant velocity. To this, write:
110 @ km/h
To the element Mobile in X, the car B, write (remember that this car begins its movement after 4 seconds):
To the element Distance XY:
Now click in the icon Solve to get the answer.
t = 30.861 s ; xfA = 942.981 m ; xfB 937.981 ; vfB = 69.839 m/s ; Status = success.