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This script is one of a few that demonstrate how to do arithmetic
in `sed`

. This is indeed possible,^{9} but must be done manually.

To increment one number you just add 1 to last digit, replacing it by the following digit. There is one exception: when the digit is a nine the previous digits must be also incremented until you don’t have a nine.

This solution by Bruno Haible is very clever and smart because
it uses a single buffer; if you don’t have this limitation, the
algorithm used in Numbering lines, is faster.
It works by replacing trailing nines with an underscore, then
using multiple `s`

commands to increment the last digit,
and then again substituting underscores with zeros.

#!/usr/bin/sed -f /[^0-9]/ d

# replace all trailing 9s by _ (any other character except digits, could # be used) :d s/9\(_*\)$/_\1/ td

# incr last digit only. The first line adds a most-significant # digit of 1 if we have to add a digit.

s/^\(_*\)$/1\1/; tn s/8\(_*\)$/9\1/; tn s/7\(_*\)$/8\1/; tn s/6\(_*\)$/7\1/; tn s/5\(_*\)$/6\1/; tn s/4\(_*\)$/5\1/; tn s/3\(_*\)$/4\1/; tn s/2\(_*\)$/3\1/; tn s/1\(_*\)$/2\1/; tn s/0\(_*\)$/1\1/; tn

:n y/_/0/

`sed`

guru Greg
Ubben wrote an implementation of the `dc`

RPN calculator!
It is distributed together with sed.