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A reduce/reduce conflict occurs if there are two or more rules that apply to the same sequence of input. This usually indicates a serious error in the grammar.
For example, here is an erroneous attempt to define a sequence
of zero or more word
groupings.
sequence: %empty { printf ("empty sequence\n"); } | maybeword | sequence word { printf ("added word %s\n", $2); } ;
maybeword: %empty { printf ("empty maybeword\n"); } | word { printf ("single word %s\n", $1); } ;
The error is an ambiguity: as counterexample generation would demonstrate
(see Generation of Counterexamples), there is more than one way to parse a single
word
into a sequence
. It could be reduced to a
maybeword
and then into a sequence
via the second rule.
Alternatively, nothing-at-all could be reduced into a sequence
via the first rule, and this could be combined with the word
using the third rule for sequence
.
There is also more than one way to reduce nothing-at-all into a
sequence
. This can be done directly via the first rule,
or indirectly via maybeword
and then the second rule.
You might think that this is a distinction without a difference, because it does not change whether any particular input is valid or not. But it does affect which actions are run. One parsing order runs the second rule’s action; the other runs the first rule’s action and the third rule’s action. In this example, the output of the program changes.
Bison resolves a reduce/reduce conflict by choosing to use the rule that
appears first in the grammar, but it is very risky to rely on this. Every
reduce/reduce conflict must be studied and usually eliminated. Here is the
proper way to define sequence
:
sequence: %empty { printf ("empty sequence\n"); } | sequence word { printf ("added word %s\n", $2); } ;
Here is another common error that yields a reduce/reduce conflict:
sequence: %empty | sequence words | sequence redirects ;
words: %empty | words word ;
redirects: %empty | redirects redirect ;
The intention here is to define a sequence which can contain either
word
or redirect
groupings. The individual definitions of
sequence
, words
and redirects
are error-free, but the
three together make a subtle ambiguity: even an empty input can be parsed
in infinitely many ways!
Consider: nothing-at-all could be a words
. Or it could be two
words
in a row, or three, or any number. It could equally well be a
redirects
, or two, or any number. Or it could be a words
followed by three redirects
and another words
. And so on.
Here are two ways to correct these rules. First, to make it a single level of sequence:
sequence: %empty | sequence word | sequence redirect ;
Second, to prevent either a words
or a redirects
from being empty:
sequence: %empty | sequence words | sequence redirects ;
words: word | words word ;
redirects: redirect | redirects redirect ;
Yet this proposal introduces another kind of ambiguity! The input
‘word word’ can be parsed as a single words
composed of two
‘word’s, or as two one-word
words
(and likewise for
redirect
/redirects
). However this ambiguity is now a
shift/reduce conflict, and therefore it can now be addressed with precedence
directives.
To simplify the matter, we will proceed with word
and redirect
being tokens: "word"
and "redirect"
.
To prefer the longest words
, the conflict between the token
"word"
and the rule ‘sequence: sequence words’ must be resolved
as a shift. To this end, we use the same techniques as exposed above, see
Using Precedence For Non Operators. One solution
relies on precedences: use %prec
to give a lower precedence to the
rule:
%precedence "word" %precedence "sequence" %%
sequence: %empty | sequence word %prec "sequence" | sequence redirect %prec "sequence" ;
words: word | words "word" ;
Another solution relies on associativity: provide both the token and the rule with the same precedence, but make them right-associative:
%right "word" "redirect" %%
sequence: %empty | sequence word %prec "word" | sequence redirect %prec "redirect" ;
Next: Mysterious Conflicts, Previous: Parser States, Up: The Bison Parser Algorithm [Contents][Index]