# Line slope calculator x-5y=-4

**Straight line given by points A[1; 1] and B[6; 2]**

## Calculation:

**Slope-intercept form of line:**y = 0.2x+0.8

**Canonical form of the line equation:**x-5y+4 = 0

**Parametric form of the line equation:**

x = 5t+1

y = t+1 ; t ∈ R

**Slope:**m = 0.2

**Slope angle of line: φ =**11°18'36″ = 0.1974 rad

**X intercept:**x

_{0}= -4

**Y intercept:**y

_{0}= q = 0.8

**Distance line from the origin:**d

_{0}= 0.7845

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; 1)

**Normal vector: n =**(1; -5)

**Midpoint of the segment AB: M =**[3.5; 1.5]

**Perpendicular Bisector equation:**5x+y-19 = 0

**Vector OA = (1; 1) ; |OA| = 1.4142**

**Vector OB = (6; 2) ; |OB| = 6.3246**

**Scalar product OA .OB = 8**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**