15.11 Example 11

In a calorimeter with 325 g of water at 20 C, is introduced 77 g of an unknown metal at 90 C. If the final temperature is 26 C, what is the specific heat of the metal? (Specific heat of water = 4187 J/kg*K).

Solution with FisicaLab

Select the Thermodynamics group and, inside this, the Calorimetry and gases module. Erase the content of the chalkboard. And add one element Calorimetry, one element Block and one element Liquid. As show the image below:

To the element Liquid, we call this Water, we have:

Name

Water

m

325 @ g

c

4187

Ti

20 @ C

Tf

26 @ C

And to the element Block, we call this Metal, we have:

Name

Metal

m

77 @ g

c

cM

Ti

90 @ C

Tf

26 @ C

Note that the final temperature is the same in both elements, as must be. To the element Calorimetry, we have:

Object 1

Water

Object 2

Metal

Object 3

0

Object 4

0

Now click in the icon Solve to get the answer:

cM = 1656.788 J/kg*K ;
Status = success.