Next: Example 8 (d), Previous: Example 6 (d), Up: Examples dynamics of particles [Contents][Index]
An A mobile of 4 kg and a B mobile of 3 kg, with velocities of 80 m/s and 110 m/s respectively, have the directions that show the image. These mobiles impact with the normal in the image. If the coefficient of restitution is 0.7, which are the velocity and direction of each mobile after the impact?
Solution with FisicaLab
Erase the content of the chalkboard and select the SI system. And add one element Collision, and two elements Mobile. As show the image below:
To the element Mobile at the left, that we assume is the A mobile, write:
A
4
80
45
vf_A
ang_A
To the other mobile, the B mobile:
B
3
110
120
vf_B
ang_B
And to the element Collision:
A
B
0.7
20
Now click in the icon Solve to get the answer:
vf_A = 34.297 m/s ; ang_A = 100.326 degrees ; vf_B = 128.916 m/s ; ang_B = 77.172 degrees ; Status = success.