11.9 Example 9

A baseball ball, of 0.22 kg, is launched with a velocity of 32 m/s horizontally. A batter hits the ball, and this take a velocity of 61 m/s at 40 degrees above the horizontal. Which is the momentum applied to the ball?

Solution with FisicaLab

Erase the content of the chalkboard and select the SI system. And add one element Stationary reference system, one element Mobile, and one element Momentum. As show the image below:

We don’t have a time data to the impact (the duration of the impact), but we assume 0.01 seconds, a reasonable time. This time is necessary to calculate the impulsive force in the element Momentum. Then, to the element Stationary reference system, write:

g

9.81

t

0.01

We assume that the ball is, initially, moving in the direction of negative X. Then in the element Mobile, we call this Ball, write:

Name

Ball

m

0.22

vi

32

angi

180

vf

61

angf

40

To the element Momentum:

Object

Ball

Imp

imp

ang

ang

fImp

f

Now click in the icon Solve to get the answer:

imp = 9.215 N*s ;  ang = 69.412 degrees ;  f = 921.472 N ;
Status = success.