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Different operators are generally assigned different precedences. By default, an operator defined by a rule like

# foo # := foo(#1,#2)

will have an extremely low precedence, so that ‘2*3+4 foo 5 == 6’ will be parsed as ‘(2*3+4) foo (5 == 6)’. To change the precedence of an operator, use the notation ‘#/p’ in place of ‘#’, where p is an integer precedence level. For example, 185 lies between the precedences for ‘+’ and ‘*’, so if we change this rule to

#/185 foo #/186 := foo(#1,#2)

then ‘2+3 foo 4*5’ will be parsed as ‘2+(3 foo (4*5))’. Also, because we’ve given the righthand expression slightly higher precedence, our new operator will be left-associative: ‘1 foo 2 foo 3’ will be parsed as ‘(1 foo 2) foo 3’. By raising the precedence of the lefthand expression instead, we can create a right-associative operator.

See Composition Basics, for a table of precedences of the standard Calc operators. For the precedences of operators in other language modes, look in the Calc source file calc-lang.el.